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Fix arithmetic instruction specs

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Originally, arithmetic instructions were in the form of

    REG2 = REG1 (OP) REG2

but then I started storing the result in REG1 (both in implementation,
and later defs of the arth instructions). So I'm updating it to match
what was actually in my head.

Signed-off-by: Alek Ratzloff <alekratz@gmail.com>
This commit is contained in:
Alek Ratzloff
2020-01-26 10:52:26 -05:00
parent 976b0689ba
commit df950c6f63
1 changed files with 10 additions and 11 deletions
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21
vm.md
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@@ -43,32 +43,32 @@ CPU flags are addressed by bit index, going from right to left.
## Arithmetic
Arithmetic instructions store their result in the last register specified.
Arithmetic instructions store their result in the first register specified.
* Add
* **Params**: REG1, REG2
* `REG2 = REG1 + REG2`
* `REG1 = REG1 + REG2`
* Mul
* **Params**: REG1, REG2
* `REG2 = REG1 * REG2`
* `REG1 = REG1 * REG2`
* Div
* **Params**: REG1, REG2
* `REG2 = REG1 / REG2`
* `REG1 = REG1 / REG2`
* Mod
* **Params**: REG1, REG2
* `REG2 = REG1 % REG2` (exact semantics TBD)
* `REG1 = REG1 % REG2` (exact semantics TBD)
* Neg
* **Params**: REG1
* `REG1 = REG1 * -1`
* And
* **Params**: REG1, REG2
* `REG2 = REG1 & REG2`
* `REG1 = REG1 & REG2`
* Or
* **Params**: REG1, REG2
* `REG2 = REG1 | REG2`
* `REG1 = REG1 | REG2`
* Xor
* **Params**: REG1, REG2
* `REG2 = REG1 ^ REG2`
* `REG1 = REG1 ^ REG2`
* Shl
* **Params**: REG1, REG2
* `REG1 = REG1 << REG2`
@@ -124,9 +124,8 @@ Arithmetic instructions store their result in the last register specified.
MEM[REG2] = REG1;
```
* StoreImm32
* (hw = half word)
* **Params**: REG1, IMM_HW
* `REG1 = IMM_HW`
* **Params**: REG1, IMM_32
* `REG1 = IMM_32`
* MemCopy
* **Params**: REG1, REG2
* `MEM[REG1] = MEM[REG2]`